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이번 문제에서는 행의 수가 50이라 작지만, 행의 개수가 많아졌을 때, 이미 본 행을 기록해서 다음에 똑같은 모양의 행이 나왔을 때, 그 행에 대해서는 이미 체크했기 때문에 보지 않고 넘어간다면 조금 더 빠를 수 있을 것 같습니다. 또한, 다음의 코드에서 j를 i+1 부터 시작하는 방법도 생각할 수 있을 것 같습니다. ssafy_algorithm_study/src/week8/BJ1034Lamp/Main.java Lines 65 to 69 in fe45305 |
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풀이
세가지 규칙
(1) 동일한 모양을 가진 행의 개수가 많을 수록 결과값이 커짐
(2) 해당행 0의 개수가 k보다 작거나 같아야함
(3) 해당 행 0의 개수와 k의 개수 홀수 짝수의 경우가 같아야함
리뷰 요청 사항
느낀점 👍